PAT甲1077字符串

PAT甲1077字符串

题目链接
1077 Kuchiguse (20分)
The Japanese language is notorious for its sentence ending particles. Personal preference of such particles can be considered as a reflection of the speaker’s personality. Such a preference is called “Kuchiguse” and is often exaggerated artistically in Anime and Manga. For example, the artificial sentence ending particle “nyan~” is often used as a stereotype for characters with a cat-like personality:

Itai nyan~ (It hurts, nyan~)

Ninjin wa iyada nyan~ (I hate carrots, nyan~)

Now given a few lines spoken by the same character, can you find her Kuchiguse?

Input Specification:
Each input file contains one test case. For each case, the first line is an integer N (2≤N≤100). Following are N file lines of 0~256 (inclusive) characters in length, each representing a character’s spoken line. The spoken lines are case sensitive.

Output Specification:
For each test case, print in one line the kuchiguse of the character, i.e., the longest common suffix of all N lines. If there is no such suffix, write nai.

Sample Input 1:
3
Itai nyan~
Ninjin wa iyadanyan~
uhhh nyan~
Sample Output 1:
nyan~
Sample Input 2:
3
Itai!
Ninjinnwaiyada T_T
T_T
Sample Output 2:
nai

题意:
给n个字符串,求出它们的最长公共后缀,如果不存在的话,就输出”nai”;

题解:
可以反转一下。然后取出第一个字符串的第一位,判断与剩下的所有字符串是否相同,如果相同,则继续判断,直到不同为止。

代码:

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#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
vector<char> v;
string s[105];
int main()
{
int n,len=10000;
cin>>n;
getchar();
for(int i=1;i<=n;i++)
{
getline(cin,s[i]);
reverse(s[i].begin(),s[i].end());
int t=s[i].length();
len=min(len,t);
}
for(int i=0;i<len;i++)
{
int flag=1;
char temp=s[1][i];
for(int j=2;j<=n;j++)
{
if(s[j][i]!=temp)
{
flag=0;
break;
}
}
if(flag==1)
v.push_back(temp);
else
break;
}
if(v.size()==0)
cout<<"nai";
else
{
for(int i=v.size()-1;i>=0;i--)
cout<<v[i];
}
}
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